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<article>
<front>
<title>Free particle on SU(2) group manifold</title>
<author>
	<fname>George</fname>
	<surname>Chavchanidze</surname>
</author>
<aff>
	<orgdiv>Department of Theoretical Physics</orgdiv>
	<orgname>A. Razmadze Institute of Mathematics</orgname>
	<street>1 Aleksidze Street</street>
	<city>Tbilisi</city>
	<postcode>0193</postcode>
	<country>Georgia</country>
</aff>
<abstract>
<title>Abstract</title>
<p>In the present paper classical and quantum dynamics 
of a free particle on <formula>SU(2)</formula> group manifold is considered.
Poisson structure of the dynamical system and commutation relations for generalized momenta are
derived. Quantization is carried out and the eigenfunctions of the Hamiltonian
are constructed in terms of coordinate free objects.
<formula>SU(2)/U(1)</formula> coset model yielding after Hamiltonian reduction free particle on 
<formula>S<sup>2</sup></formula> sphere is considered
and Hamiltonian reduction of coset model is carried out on both classical and quantum level.</p>
</abstract>
<supmatl>
<p>
	<emph>Keywords:</emph>
	<keyphras>Dynamics on group manifold</keyphras>,
	<keyphras>Quantization on group manifold</keyphras>,
</p>
<p><emph>MSC 2000:</emph> 70H33; 70H06; 53Z05</p>
</supmatl>
</front>
<chapter>
<section id="h1">
<title>Lagrangian description</title>
<p>The dynamics of a free particle on <formula>SU(2)</formula> group manifold is described by the Lagrangian
<dformula>
L = 〈g<sup>− 1</sup>ġg<sup>− 1</sup>ġ〉
</dformula>
where <formula>g ∈ SU(2)</formula> and <formula>〈 〉</formula> denotes the normalized trace
<dformula>
〈 · 〉 = − ½Tr( · )
</dformula>
which defines a scalar product in <formula>su(2)</formula> algebra. This Lagrangian gives rise to equations of motion
<dformula>
<fraction><num>d</num><den>dt</den></fraction>g<sup>− 1</sup>ġ = 0
</dformula>
that describe dynamics of particle on group manifold.
Also, one can notice that it has <formula>SU(2)</formula> "right" and <formula>SU(2)</formula> "left" symmetry.
It means that it is invariant under the following transformations
<dformula>
g       →      h<inf>1</inf>g<break/>
g       →    gh<inf>2</inf>
</dformula>
where <formula>h<inf>1</inf>, h<inf>2</inf> ∈ SU(2)</formula>
</p>
<p>According to the Noether's theorem these symmetries lead to the matrix valued conserved quantities
<dformula>
C = g<sup>− 1</sup>ġ           <fraction><num>d</num><den>dt</den></fraction>C = 0
</dformula>
and
<dformula>
S = ġg<sup>− 1</sup>           <fraction><num>d</num><den>dt</den></fraction>S = 0
</dformula>
To construct integrals of motion out of <formula>C</formula> and <formula>S</formula> let us introduce the basis of
<formula>su(2)</formula> algebra — three matrices:
<dformula>
T<inf>1</inf> =
<fence lpost="(" rpost=")"><array>
<arrayrow>
<arraycel>i</arraycel>
<arraycel>0</arraycel>
</arrayrow>
<arrayrow>
<arraycel>0</arraycel>
<arraycel>− i</arraycel>
</arrayrow>
</array></fence>
     
T<inf>2</inf> =
<fence lpost="(" rpost=")"><array>
<arrayrow>
<arraycel>0</arraycel>
<arraycel>− 1</arraycel>
</arrayrow>
<arrayrow>
<arraycel>1</arraycel>
<arraycel>0</arraycel>
</arrayrow>
</array></fence>
     
T<inf>3</inf> =
<fence lpost="(" rpost=")"><array>
<arrayrow>
<arraycel>0</arraycel>
<arraycel>i</arraycel>
</arrayrow>
<arrayrow>
<arraycel>i</arraycel>
<arraycel>0</arraycel>
</arrayrow>
</array></fence>

</dformula>
The elements of <formula>su(2)</formula> are traceless anti-hermitian matrices, and any
<formula>A ∈ su(2)</formula> can be parameterized in the following way
<dformula>
A = A<sup>n</sup>T<inf>n</inf>            n = 1, 2, 3
</dformula>
Scalar product <dformula>
AB = 〈AB〉 = − ½Tr(AB)
</dformula> ensures that
<dformula>
A<sup>n</sup> = 〈AT<inf>n</inf>〉            (〈T<inf>n</inf>T<inf>m</inf>〉 = δ<inf>nm</inf>)
</dformula>
Now we can introduce six functions
<dformula>
C<inf>n</inf> = 〈T<inf>n</inf>C〉          n = 1, 2, 3           C = C<sup>n</sup>T<inf>n</inf><break/>
S<inf>n</inf> = 〈T<inf>n</inf>S〉           n = 1, 2, 3            S = S<sup>n</sup>T<inf>n</inf>
</dformula>
which are integrals of motion.</p>
<p>Conservation of <formula>C</formula> and <formula>S</formula> leads to general solution of Euler-Lagrange equations
<dformula>
<fraction><num>d</num><den>dt</den></fraction>g<sup>− 1</sup>ġ = 0           ⇒           g<sup>− 1</sup>ġ = const<break/>
g = e<sup>Ct</sup>g(0)
</dformula>
These are well known geodesics on Lie group.
</p>
</section>
<section id="h2">
<title>Hamiltonian description</title>

<p>Working in a first order Hamiltonian formalism we can construct new Lagrangian
which is equivalent to the initial one
<dformula>
Λ = 〈C(g<sup>− 1</sup>ġ − v)〉 + ½〈v<sup>2</sup>〉
</dformula>
in sense that variation of C provides
<dformula>
g<sup>− 1</sup>ġ = v
</dformula>
and <formula>Λ</formula> reduces to <formula>L</formula>.
Variation of <formula>v</formula> gives <formula>C = v</formula> and therefore we can rewrite
equivalent Lagrangian <formula>Λ</formula> in terms of C and g variables
<dformula>
Λ = 〈Cg<sup>− 1</sup>ġ〉 − ½ 〈C<sup>2</sup>〉
</dformula>
where function
<dformula>
H = ½〈C<sup>2</sup>〉
</dformula>
plays the role of Hamiltonian and
one-form <formula>〈Cg<sup>− 1</sup>dg〉</formula> is a symplectic potential <formula>θ</formula>.
External differential of <formula>θ</formula> is the symplectic form
<dformula>
ω = dθ = − 〈g<sup>− 1</sup>dg ∧ dC〉 − 〈Cg<sup>− 1</sup> dg ∧ g<sup>− 1</sup>dg〉
</dformula>
that determines Poisson brackets, the form of Hamilton's equation
and provides isomorphism between vector fields and one-forms
<dformula>
X      →      i<inf>X</inf>ω
</dformula>
For any smooth <formula>SU(2)</formula> valued smooth function
<formula>f ∈ SU(2)</formula> one can define Hamiltonian vector field <formula>X<inf>f</inf></formula> by
<dformula>
i<inf>X<inf>f</inf></inf>ω = − df
</dformula>
where <formula>i<inf>X</inf>ω</formula> denotes the contraction of <formula>X</formula> with <formula>ω</formula>.
According to its definition Poisson bracket of two functions is
<dformula>
{f , g} = L<inf>X<inf>f</inf></inf>g = i<inf>X<inf>f</inf></inf>dg = ω(X<inf>f</inf> , X<inf>g</inf>)
</dformula>
where <formula>L<inf>X<inf>f</inf></inf>g</formula> denotes Lie derivative of <formula>g</formula> with respect to vector filed <formula>X<inf>f</inf></formula>.
The skew symmetry of <formula>ω</formula> provides skew symmetry of Poisson bracket.</p>
<p>Hamiltonian vector fields that correspond to <formula>C<inf>n</inf>, S<inf>m</inf></formula> and <formula>g</formula> functions are
<dformula>
X<inf>n</inf> = X<inf>C<inf>n</inf></inf> = ([C ,T<inf>n</inf>] , gT<inf>n</inf>)<break/>
Y<inf>m</inf> = X<inf>S<inf>m</inf></inf> = ([C , gT<inf>m</inf>g<sup>− 1</sup>] , T<inf>m</inf>g )
</dformula>
and give rise to the following commutation relations
<dformula>
{S<inf>n</inf> , S<inf>m</inf>} = − 2ε<inf>nm</inf><sup>k</sup> S<inf>k</inf><break/>
{C<inf>n</inf> , C<inf>m</inf>} = 2ε<inf>nm</inf><sup>k</sup> C<inf>k</inf><break/>
{C<inf>n</inf> , S<inf>m</inf>} = 0<break/>
{C<inf>n</inf> , g} = gT<inf>n</inf><break/>
{S<inf>m</inf> , g} = T<inf>m</inf>g
</dformula>
The results are natural. <formula>C</formula> and <formula>S</formula> that correspond respectively to the "right"
and "left" symmetry commute with each other and independently form <formula>su(2)</formula>
algebras. Now knowing Poisson bracket structure one can write down Hamilton's equations
<dformula>
ġ = {H , g} = gR
</dformula>
<dformula>
Ċ = {H , C} = 0
</dformula>
</p>
</section>

<section id="h3">
<title>Quantization</title>

<p>Let's introduce operators
<dformula>
Ĉ<inf>n</inf> = <fraction><num>i</num><den>2</den></fraction>L<inf>X<inf>n</inf></inf>
</dformula>
<dformula>
Ŝ<inf>m</inf> = − <fraction><num>i</num><den>2</den></fraction>L<inf>Y<inf>m</inf></inf>
</dformula>
They act on the square integrable functions (see Appendix A) on <formula>SU(2)</formula> and satisfy quantum
commutation relations
<dformula>
[Ŝ<inf>n</inf> , Ŝ<inf>m</inf>] = iε<inf>nm</inf><sup>k</sup> Ŝ<inf>k</inf>
</dformula>
<dformula>
[Ĉ<inf>n</inf> , Ĉ<inf>m</inf>] = iε<inf>nm</inf><sup>k</sup> Ĉ<inf>k</inf>
</dformula>
<dformula>
[Ĉ<inf>n</inf> , Ŝ<inf>m</inf>] = 0
</dformula>
The Hamiltonian is defined as
<dformula>
Ĥ = Ĉ<sup>2</sup> = Ŝ<sup>2</sup>
</dformula>
and the complete set of observables that commute with each other is
<dformula>
Ĥ,           Ĉ<inf>a</inf>,            Ŝ<inf>b</inf>
</dformula>
with some fixed a and b. Using a simple generalization of a well known algebraic construction (see Appendix B)
one can check that the eigenvalues of the quantum observables
<formula>Ĥ, Ĉ<inf>a</inf></formula> and <formula>Ŝ<inf>b</inf></formula> have the form
<dformula>
Ĥψ<inf>jsc</inf> = j(j + 1)ψ<inf>jsc</inf>
</dformula>
where <formula>j</formula> takes positive integer and half integer values
<dformula>
j = 0, <fraction><num>1</num><den>2</den></fraction>, 1, <fraction><num>3</num><den>2</den></fraction>, 2 ...
</dformula>
<dformula>
Ĉ<inf>a</inf>ψ<inf>jsc</inf> = cψ<inf>jsc</inf>
</dformula>
<dformula>
Ŝ<inf>b</inf>ψ<inf>jsc</inf> = sψ<inf>jsc</inf>
</dformula>
with <formula>c</formula> and <formula>s</formula> taking values in the following range
<dformula>
− j, − j + 1, ... , j − 1, j
</dformula>
Further we construct the corresponding eigenfunctions
<formula>ψ<inf>jsc</inf></formula>. The first step of this construction is to note that
the function <formula>〈Tg〉</formula> where <formula>T = (1 + iT<inf>a</inf>)(1 + iT<inf>b</inf>)</formula>
is an eigenfunction of <formula>Ĥ, Ĉ<inf>a</inf></formula> and <formula>Ŝ<inf>b</inf></formula>
with eigenvalues <formula>¾, ½, ½</formula> respectively.
Proof of this proposition is straightforward.
Using <formula>〈Tg〉</formula> one can construct the complete set of eigenfunctions of
<formula>Ĥ, Ĉ<inf>a</inf></formula> and <formula>Ŝ<inf>b</inf></formula> operators
<dformula id="e37">
ψ<inf>jsc</inf> =
Ŝ<inf>−</inf><sup>j − s</sup>Ĉ<inf>−</inf><sup>j − c</sup>〈Tg〉<sup>2j</sup>
</dformula> in the manner described in Appendix B.</p>
</section>

<section id="h4">
<title>Free particle on S² as a SU(2)/U(1) coset model</title>

<p>Free particle on <formula>2D</formula> sphere can be obtained from our model by gauging <formula>U(1)</formula> symmetry.
In other words let's consider the following local gauge transformations
<dformula id="e38">g      →      h(t)g
</dformula>
Where <formula>h(t) ∈ U(1) ⊂ SU(2)</formula> is an element of <formula>U(1)</formula>. Without loss of generality we can take
<dformula>
h = e<sup>β(t)T<inf>3</inf></sup>
</dformula>
Since <formula>T<inf>3</inf></formula> is antihermitian <formula>h(t) ∈ U(1)</formula> and since <formula>h(t)</formula> depends on <formula>t</formula> Lagrangian
<dformula id="e40">
L = 〈g<sup>− 1</sup>ġg<sup>− 1</sup>ġ〉
</dformula>
is not invariant under <formref rid="e38">(38)</formref> local gauge transformations.</p>
<p>To make <formref rid="e40">(40)</formref> gauge invariant we should replace time derivative
with covariant derivative
<dformula>
<fraction><num>d</num><den>dt</den></fraction>g     →    ∇g = <fence lpost="(" rpost=")"><fraction><num>d</num><den>dt</den></fraction> + B</fence>g
</dformula>
where <formula>B</formula> can be represented as follows
<dformula>
B = bT<inf>3</inf> ∈ su(2)
</dformula>
with transformation rule
<dformula>
B      →     hBh<sup>− 1</sup> − <fraction><num>dh</num><den>dt</den></fraction>h<sup>− 1</sup>
</dformula>
or in terms of <formula>b</formula> variable
<dformula>
b    →     b − <fraction><num>dβ</num><den>dt</den></fraction>
</dformula>
The new Lagrangian
<dformula id="e45">
L<inf>G</inf> = 〈g<sup>− 1</sup>∇gg<sup>− 1</sup>∇g〉
</dformula>
is invariant under <formref rid="e38">(38)</formref> local gauge transformations. But this
Lagrangian as well as every gauge invariant Lagrangian is singular.
It contains additional non-physical degrees of freedom. To
eliminate them we should eliminate <formula>B</formula> using Lagrange equations
<dformula>
<fraction><num>∂L<inf>G</inf></num><den>∂B</den></fraction>      →      b = − 〈ġg<sup>− 1</sup>T<inf>3</inf>〉
</dformula>
put it back in <formref rid="e45">(45)</formref> and rewrite last obtained Lagrangian in terms of gauge invariant variables.
<dformula>
L<inf>G</inf> = 〈(g<sup>− 1</sup>ġ − S<inf>3</inf>T<inf>3</inf>)<sup>2</sup>〉
</dformula>
It's obvious that the following
<dformula>
Z = g<sup>− 1</sup>T<inf>3</inf>g ∈ su(2)
</dformula>
element of <formula>su(2)</formula> algebra is gauge invariant. Since <formula>Z ∈ su(2)</formula> it can be parameterized as follows
<dformula>
Z = z<sup>a</sup>T<inf>a</inf>
</dformula>
where <formula>z<sup>a</sup></formula> are real functions on <formula>SU(2)</formula>
<dformula>
z<inf>a</inf> = 〈ZT<inf>a</inf>〉
</dformula>
</p>
<p>
So we have three gauge invariant variables <formula>z<sup>a</sup> (a = 1, 2, 3)</formula> but it's easy to
check that only two of them are independent. Indeed
<dformula>
〈Z<sup>2</sup>〉 = 〈g<sup>− 1</sup>T<inf>3</inf>gg<sup>− 1</sup>T<inf>3</inf>g〉 = 〈T<inf>3</inf><sup>2</sup>〉 = 1
</dformula>
otherwise
<dformula>
〈Z<sup>2</sup>〉 = 〈z<sup>a</sup>T<inf>a</inf>z<sup>b</sup>T<inf>b</inf>〉 = z<sup>a</sup>z<inf>a</inf>
</dformula>
</p>
<p>So configuration space of <formula>SU(2)/U(1)</formula> coset model is sphere.
By direct calculations one can check that after being rewritten in terms of gauge invariant variables <formula>L<inf>G</inf></formula>
takes the form
<dformula>
L<inf>G</inf> = ¼〈Z<sup>− 1</sup>ŻZ<sup>− 1</sup>Ż〉
</dformula>
This Lagrangian describes free particle on the sphere. Indeed,
since <formula>Z = z<sup>a</sup>T<inf>a</inf></formula> it's easy to show that
<dformula>
L<inf>G</inf> = ¼〈Z<sup>− 1</sup>ŻZ<sup>− 1</sup>Ż〉 =
¼〈ZŻZŻ〉 = ½ż<sup>a</sup>ż<inf>a</inf>
</dformula>
So <formula>SU(2)/U(1)</formula> coset model describes free particle on <formula>S<sup>2</sup></formula> manifold.
</p>
</section>

<section id="h5">
<title>Quantization of the coset model.</title>

<p>Working in a first order Hamiltonian formalism one can introduce equivalent Lagrangian
<dformula>
Λ<inf>G</inf> = 〈C(g<sup>− 1</sup>ġ − u)〉 + ½ 〈(u + g<sup>− 1</sup>Bg)<sup>2</sup>〉
</dformula>
variation of <formula>u</formula> provides
<dformula>
C = u + g<sup>− 1</sup>Bg <break/>
u = C − g<sup>− 1</sup>Bg
</dformula>
Rewriting <formula>Λ<inf>G</inf></formula> in terms of <formula>C</formula> and <formula>g</formula> leads to
<dformula>
Λ<inf>G</inf> = 〈Cg<sup>− 1</sup>ġ〉 − ½ 〈C<sup>2</sup>〉 − 〈BgCg<sup>− 1</sup>〉 = 〈Cg<sup>− 1</sup>ġ〉 <break/>
− ½ 〈C<sup>2</sup>〉 − b〈gCg<sup>− 1</sup>T<inf>3</inf>〉 = 
〈Cg<sup>− 1</sup>ġ〉 − ½ 〈C<sup>2</sup>〉 − bS<inf>3</inf>
</dformula>
Due to the gauge invariance of <formula>Λ<inf>G</inf></formula> we obtain constrained Hamiltonian system,
where <formula>〈Cg<sup>− 1</sup>dg〉</formula> is symplectic potential, function
<dformula>
H =
½〈C<sup>2</sup>〉
</dformula> plays the role of Hamiltonian and
<formula>b</formula> is a Lagrange multiple leading to the first class constrain
<dformula id="e59">
φ = 〈gCg<sup>− 1</sup>T<inf>3</inf>〉 = 〈ST<inf>3</inf>〉 = S<inf>3</inf> = 0
</dformula>
So coset model is equivalent to the initial one with <formref rid="e59">(59)</formref> constrain.
Using technique of the constrained quantization, instead of
quantizing coset model we can subject quantum model that corresponds to the free particle on <formula>SU(2)</formula>,
to the following operator constrain
<dformula>
Ŝ<inf>3</inf>|ψ〉 = 0
</dformula>
Hilbert space of the initial system, that is linear span of
<dformula>
ψ<inf>jcs</inf>           j = 0, <fraction><num>1</num><den>2</den></fraction>, 1, <fraction><num>3</num><den>2</den></fraction>, 2, ...
</dformula>
wave functions, reduces to
the linear span of
<dformula>
ψ<inf>jc0</inf>            j = 0, 1, 2, 3, ...
</dformula>
wave functions. Indeed,
<formula>Ŝ<inf>3</inf>ψ<inf>jcs</inf> = 0</formula> implies <formula>s = 0</formula>, and if <formula>s = 0</formula> then <formula>j</formula> is integer.
Thus <formula>c</formula> takes <formula>− j, − j + 1, ..., j − 1, j</formula> integer values only.
Wave functions <formula>ψ<inf>jcs</inf></formula> rewriten in terms of gauge invariant
variables up to a constant multiple should coincide with well known
spherical harmonics
<dformula>
ψ<inf>jc0</inf> ∼ J<inf>jc</inf>
</dformula>
One can check the following
<dformula>
ψ<inf>jc0</inf> ∼ Ŝ<inf>−</inf><sup>j</sup>Ĉ<inf>−</inf><sup>j − c</sup> 〈Tg〉<sup>2j</sup> 
∼ Ĉ<inf>−</inf><sup>j − c</sup> 〈T<inf>+</inf>g<sup>− 1</sup>T<inf>3</inf>g〉<sup>j</sup><break/>
 
∼ Ĉ<inf>−</inf><sup>j − c</sup>sin<sup>j</sup>θe<sup>ijθ</sup> 
∼ Ĉ<inf>−</inf><sup>j − c</sup>J<inf>jj</inf> ∼J<inf>jc</inf>
</dformula>
This is an example of using large initial model in quantization of
coset model.</p>
</section>
</chapter>
<appmat>
<appendix>
<title>Appendix A</title>

<p>Scalar product in Hilbert space is defined as follows
<dformula id="e65">
〈ψ<inf>1</inf>|ψ<inf>2</inf>〉 =
<subform><roman>∫</roman><bottom>SU(2)</bottom></subform>
<subform><roman>∏</roman><bottom>a = 1</bottom><top>3</top></subform>
〈g<sup>− 1</sup>dgT<inf>a</inf>〉(ψ<inf>1</inf>)<sup>†</sup>ψ<inf>2</inf>
</dformula>
It's easy to prove that under this scalar product operators
<formula>Ĉ<inf>n</inf></formula> and <formula>Ŝ<inf>m</inf></formula> are hermitian.
Indeed
<dformula>
〈ψ<inf>1</inf>|Ĉ<inf>n</inf>ψ<inf>2</inf>〉 =
<subform><roman>∫</roman><bottom>SU(2)</bottom></subform>
<subform><roman>∏</roman><bottom>a = 1</bottom><top>3</top></subform>
〈g<sup>− 1</sup>dgT<inf>a</inf>〉(ψ<inf>1</inf>)<sup>†</sup>
<fence lpost="(" rpost=")"><fraction><num>i</num><den>2</den></fraction>L<inf>X<inf>n</inf></inf>ψ<inf>2</inf></fence> <break/>
= <subform><roman>∫</roman><bottom>SU(2)</bottom></subform>
<subform><roman>∏</roman><bottom>a = 1</bottom><top>3</top></subform>
〈g<sup>− 1</sup>dgT<inf>a</inf>〉<subform><fence lpost="(" rpost=")"><fraction><num>i</num><den>2</den></fraction>L<inf>X<inf>n</inf></inf>ψ<inf>1</inf></fence><sup>†</sup></subform>ψ<inf>2</inf>
</dformula>
Where integration by part has been used and the additional term coming from measure
<dformula>
<subform><roman>∏</roman><bottom>a = 1</bottom><top>3</top></subform> 〈g<sup>− 1</sup>dgT<inf>a</inf>〉
</dformula>
vanished since
<dformula>
L<inf>X<inf>n</inf></inf>〈g<sup>− 1</sup>dgT<inf>a</inf>〉 = 0
</dformula>
For more transparency one can introduce the following parameterization of
<formula>SU(2)</formula>. For any <formula>g ∈ SU(2)</formula>.
<dformula>
g = e<sup>q<sup>a</sup>T<inf>a</inf></sup>
</dformula>
Then the symplectic potential takes the form
<dformula>
〈Cg<sup>− 1</sup>dg〉 = C<inf>a</inf>dq<sup>a</sup>
</dformula>
and scalar product becomes
<dformula>
〈ψ<inf>1</inf>|ψ<inf>2</inf>〉 =
<subform><roman>∫</roman><bottom>0</bottom><top>2π</top></subform>
<subform><roman>∫</roman><bottom>0</bottom><top>2π</top></subform>
<subform><roman>∫</roman><bottom>0</bottom><top>2π</top></subform>
d<sup>3</sup>q(ψ<inf>1</inf>)<sup>†</sup>ψ<inf>2</inf>
</dformula>
that coincides with <formref rid="e65">(65)</formref> because of
<dformula>
dq<inf>a</inf> = 〈g<sup>− 1</sup>dg T<inf>a</inf>〉
</dformula>
</p>
</appendix>
<appendix>
<title>Appendix B</title>
<p>Without loss of generality we can take
<formula>Ĥ, Ŝ<inf>3</inf></formula> and
<formula>Ĉ<inf>3</inf></formula> as a complete set of observables.
Assuming that operators <formula>Ĥ, Ŝ<inf>3</inf></formula> and <formula>Ĉ<inf>3</inf></formula>
have at least one common eigenfunction
<dformula>
Ĥψ = Eψ<break/>
Ĉ<inf>3</inf>ψ = cψ<break/>
Ŝ<inf>3</inf>ψ = sψ
</dformula>
it is easy to show that eigenvalues of <formula>Ĥ</formula> are non-negative <formula>E ≥ 0</formula>
and conditions
<dformula id="e74">
E − c<sup>2</sup> ≥ 0<break/>
E − s<sup>2</sup> ≥ 0
</dformula>
are satisfied. Indeed, operators <formula>Ĉ</formula> and <formula>Ŝ</formula> are selfadjoint so
<dformula>
〈ψ|Ĥ|ψ〉 = 〈ψ|Ĉ<sup>2</sup>|ψ〉 = 〈ψ|Ĉ<inf>a</inf>Ĉ<sup>a</sup>|ψ〉 =
〈ψ|(Ĉ<inf>a</inf>)<sup>†</sup>Ĉ<sup>a</sup>|ψ〉 =<break/>
〈Ĉ<inf>a</inf>ψ|Ĉ<sup>a</sup>ψ〉 = ∥Ĉ<inf>a</inf>ψ∥ ≥ 0
</dformula>
To prove <formref rid="e74">(74)</formref> we shall consider
<formula>Ĉ<inf>1</inf><sup>2</sup> + Ĉ<inf>2</inf><sup>2</sup></formula> and
<formula>Ŝ<inf>1</inf><sup>2</sup> + Ŝ<inf>2</inf><sup>2</sup></formula> operators
<dformula>
〈ψ|Ĉ<inf>1</inf><sup>2</sup> + Ĉ<inf>2</inf><sup>2</sup>|ψ〉 =
∥Ĉ<inf>1</inf> ψ∥ + ∥Ĉ<inf>2</inf> ψ∥ ≥ 0
</dformula>
and
<dformula>
〈ψ|Ĉ<inf>1</inf><sup>2</sup> + Ĉ<inf>2</inf><sup>2</sup>|ψ〉 =
〈ψ|Ĥ − Ĉ<inf>3</inf><sup>2</sup>|ψ〉 = (E − c<sup>2</sup>)〈ψ|ψ〉
</dformula>
thus <formula>E − c<sup>2</sup> ≥ 0</formula>.</p>
<p>Now let's introduce new operators
<dformula>
Ĉ<inf>+</inf> = iĈ<inf>1</inf> + Ĉ<inf>2</inf>            Ĉ<inf>−</inf> =
iĈ<inf>1</inf> − Ĉ<inf>2</inf>
</dformula>
<dformula>
Ŝ<inf>+</inf> = iŜ<inf>1</inf> + Ŝ<inf>2</inf>            Ŝ<inf>−</inf> =
iŜ<inf>1</inf> − Ŝ<inf>2</inf>
</dformula>
These operators are not selfadjoint, but <formula>(Ĉ<inf>−</inf>)<sup>†</sup> = Ĉ<inf>+</inf></formula> and
<formula>(Ŝ<inf>−</inf>)<sup>†</sup> = Ŝ<inf>+</inf></formula>
and they fulfill the following commutation relations
<dformula>
[Ĉ<inf>±</inf> , Ĉ<inf>3</inf>] = ± Ĉ<inf>±</inf>           [Ŝ<inf>±</inf> , Ŝ<inf>3</inf>] = ± Ŝ<inf>±</inf>
</dformula>
<dformula>
[Ĉ<inf>+</inf> , Ĉ<inf>−</inf>] = 2Ĉ<inf>3</inf>           [Ŝ<inf>+</inf> , Ŝ<inf>−</inf>] = 2Ŝ<inf>3</inf>
</dformula>
<dformula>
[Ĉ<inf>•</inf> , Ŝ<inf>•</inf>] = 0
</dformula>
where <formula>•</formula> takes values <formula>+, −, 3</formula> using these commutation relations it is easy to show
that if <formula>ψ<inf>λcs</inf></formula> is eigenfunction of
<formula>Ĥ, Ŝ<inf>3</inf></formula> and
<formula>Ĉ<inf>3</inf></formula> with corresponding eigenvalues :
<dformula>
Ĥψ<inf>λcs</inf> = λψ<inf>λcs</inf><break/>
Ŝ<inf>3</inf>ψ<inf>λcs</inf> = sψ<inf>λcs</inf><break/>
Ĉ<inf>3</inf>ψ<inf>λcs</inf> = cψ<inf>λcs</inf>
</dformula>
then <formula>Ĉ<inf>±</inf>ψ<inf>λcs</inf></formula> and
<formula>Ŝ<inf>±</inf>ψ<inf>λcs</inf></formula>
are the eigenfunctions with corresponding eigenvalues
<formula>λ, s ± 1, c</formula> and <formula>λ , s, c ± 1</formula>.
Consequently using <formula>Ĉ<inf>±</inf>, Ŝ<inf>±</inf></formula> operators one can construct
a family of eigenfunctions with eigenvalues
<dformula id="e84">
c, c ± 1, c ± 2, c ± 3, ...<break/>
s, s ± 1, s ± 2, s ± 3, ...
</dformula>
but conditions <formref rid="e74">(74)</formref> give restrictions on a possible range of eigenvalues.
Namely we must have
<dformula>
λ − c<sup>2</sup> ≥ 0<break/>
λ − s<sup>2</sup> ≥ 0
</dformula>
In other words, in order to interrupt <formref rid="e84">(84)</formref> sequences we must assume
<dformula>
Ŝ<inf>+</inf> ψ<inf>λcj</inf> = 0            Ŝ<inf>−</inf>ψ<inf>λc, − j</inf> = 0<break/>
Ĉ<inf>+</inf>ψ<inf>λks</inf> = 0           Ĉ<inf>−</inf>ψ<inf>λ, − ks</inf> = 0
</dformula>
for some <formula>j</formula> and <formula>k</formula>, therefore <formula>s</formula> and <formula>c</formula> could take only the following values
<dformula>
− j, − j + 1, ... , j − 1, j<break/>
− k, − k + 1, ... , k − 1, k
</dformula>
The number of values is <formula>2j + 1</formula> and <formula>2k + 1</formula> respectively. Since number of values
should be integer, <formula>j</formula> and <formula>k</formula> should take integer or half integer values
<dformula>
j = 0, <fraction><num>1</num><den>2</den></fraction>, 1, <fraction><num>3</num><den>2</den></fraction>, 2, ...<break/>
k = 0, <fraction><num>1</num><den>2</den></fraction>, 1, <fraction><num>3</num><den>2</den></fraction>, 2, ...
</dformula>
Now using commutation relations we can rewrite <formula>Ĥ</formula> in terms of
<formula>Ĉ<inf>±</inf>, Ĉ<inf>3</inf></formula> operators
<dformula>
Ĥ = Ĉ<inf>+</inf> Ĉ<inf>−</inf> + Ĉ<inf>3</inf><sup>2</sup> + Ĉ<inf>3</inf>
</dformula>
and it is clear that <formula>j = k</formula> and <formula>λ = j(j + 1) = k(k + 1)</formula>
</p>
</appendix>
</appmat>
<back>
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